17. A small point-like object is thrown horizontally off of a 50.0-m high buildi

Question

17. A small point-like object is thrown horizontally off of a 50.0-m high building with an initial speed of 10.0 m/s. At any point along the trajectory there is an acceleration component tangential to the trajectory and an acceleration component perpendicular to the trajectory. How many seconds after the object is thrown is the tangential component of the acceleration of the object equal to twice the perpendicular component of the acceleration of the object? Ignore air resistance (a) 2.00 s (b) 1.50 s (c) 1.00 s (d) 0.50 (e) The building is not high enough for this to occur

Explanation / Answer

It will be when the trajectory makes angle arctan(2) with horizontal.

It means when vertical component of velocity is 2*10 = 20 m/s.

t = Vy/g = 20/10 = 2 sec

option a is correct.

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