(14%) Problem 4: A man stands in front of a vertical plane mirror, as shown in t
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(14%) Problem 4: A man stands in front of a vertical plane mirror, as shown in the figure. His eyes are 1.85 m above the floor and the top of his head is 0.13 m higher than that. h, Otheexpertta.com 50% Part (a) Find the height above the floor, in meters, of the bottom edge of the shortest mirror in which he can see both the top of his head and his feet. This height is denoted hb in the figure. 50% Part (b) Find the height above the floor, in meters, of the top edge of the shortest mirror in which he can see both the top of his head and his feet. This height is denoted ht in the figure. Grade Summary Deductions 2% Potential 98%Explanation / Answer
a) a = 0.13 / 2 = 0.065 m
b = 1.85 / 2 = 0.925 m
total height = 1.85 + 0.13 = 1.98 m
height of the bottom edge of shortest mirror = 0.925 m
b) L = h - (a + b) = 1.98 - (0.065 + 0.925) = 0.99 m
b + L = 0.925 + 0.99 = 1.915 m
height of the top edge of shortest mirror = 1.915 m
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