The Hyperkoop is a propoeed form of high-speed transportation that accelerates c

Question

The Hyperkoop is a propoeed form of high-speed transportation that accelerates cylindrical pods that can carry up to 28 passengers in a low pressure tube at speeds of 760 mph. In a whitepaper published by Elon Musk (http:/.spacex.com/sites/spacex/tilea/ hyperloop.alpha pdt), a 380 mile route between L.A. and San Francisco is discussed and the following constraints are introduced: The route should follow existing freeways (Le. 1-5) as closely as possible, the maxinm acceleration should be lmited to 0.5 g for rider comlort, the maximoum speed should be limited to 760 mph to avoid sonic booms. By levitating the pods using either air pressure or magnetism and evacuating most of the air from the tube, the pods can be made virtually frictionless. The pods would be accelerated up to cruising speed using linear induction motors (a line of electromagnets built into the track that act on the pod going over them). For this assignment assume an empty pod has a mass of 3100 kg, and that each rider has an average mass of 65.0 kg 1. What is the foree necessary to accelerate a full pod on a horizontal track with an acceleration of 0.5 g? 2. How long would the linear induction motor need to be to bring the fally loaded pod to cruising speed with this force 3. How mach work is being done by the motors when accelerating a fully loaded pod from rest to cruising speed? Compare this to the kinetic energy of the pod at cruising speed. So far we have completely neglected air resistance, but even in the low pressure of the tube, there is expected to be about 320 N of drag. Linear motors would be pland along the track to pendically boost the speed of the capsule to compensate for the dgml due to drag How far can a capsule coast if it starts at fall speed before it has slowed to 710 mph?

Explanation / Answer

Q8. From 7. power consumeed per capsule due to drag, P = 105148.60 W

now as all the power that is used is used to overcome drag

hence total power used for 40 capsules

Ptot = P*40 = 605944 W

Q9. Power output of a typical solar panel per unit area is about 250 W per m^2

now, for generating Ptot, area of solar panels required, A = Ptot/250 = 2423.776 m^2

for length of the loop, l = 380 miles = 611551 m, width of solar panel required, w = 2423.776/611551 = 0.39633 cm

hence this is a small width which can be placed over the hyper loop, hence all this power can be generated using the solar panels plasced above the hyper loop

Q10. number of passangers in one pod, n = 28 passengers

energy used per pod per mile , E = 320*1609.34 = 514988.8 J

energy consumed per passenger = E/28 = 18392.457 J

ennergy consumption per passenger per mile in a typical mile is about 175 J per person ( for 4 people travelling in a car)

hence hyperloop consumes much more energy than a person would spend in a typical car

Q11. let the minimum radius be r

then maximum acceleration = 0.5g

for speed of v = 760 mph = 339.75 m/s

v^2/r = 0.5*9.81

r = 23533.1422 m

r = 14.6228 miles

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.