THIS IS DYNAMYCS QUESTION. ANSWER MUST BE EXACTLY 4 S.F PLEASEEEEE!!!!! A planar

Question

THIS IS DYNAMYCS QUESTION. ANSWER MUST BE EXACTLY 4 S.F PLEASEEEEE!!!!!

A planar force decribed by (F,Py) (1.3t + 1.1,-2.9)N (where tis in seconds) acts on a body of mass 2kg from t The body's initial velocity is 2.7m/s in the r-direction. (a) What is the z-component of the impulse of the force after 3.5s? 0. (b) what is the y-component of the impulse of the force after 3.5s? e) What is the magnitude of the body's velocity after 3.5s?7 (d) What is the magnitude of the angle between the velocity vector and the z-axis after 3.5s7

Explanation / Answer

a = F / m

a = (1.3t + 1.1 /2 , -2.9/2 )

a = (0.65t + 0.55, - 1.45 ) m/s^2

dv/dt = 0.65t + 0.55

vf - v0 = 0.325 t^2 + 0.55 t

vfx - 2.7 = (0.325 x 3.5^2) + (0.55 x 3.5)

vfx = 8.61 m/s

vfy = 2.9 x 3.5 = - 10.15 m/s

(A) impulse = change in momentum

= 11.82 kg m/s

(b) Iy = - 20.3 kg m / s

(c) vf = sqrt(vfx^2 + vfy^2) = 13.3 m/s

(D) theta = - tan^-1(10.15/8.61) = - 50 deg

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