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a 2.50 kg object is attached to the end of a 2.00 m long rope and is spun in a v

ID: 3281242 • Letter: A

Question

a 2.50 kg object is attached to the end of a 2.00 m long rope and is spun in a vertical circle. Calculate the speed of the object at the bottom of the circle is the tension in the rope is 49.0N.
a 2.50 kg object is attached to the end of a 2.00 m long rope and is spun in a vertical circle. Calculate the speed of the object at the bottom of the circle is the tension in the rope is 49.0N.
a 2.50 kg object is attached to the end of a 2.00 m long rope and is spun in a vertical circle. Calculate the speed of the object at the bottom of the circle is the tension in the rope is 49.0N.

Explanation / Answer

Given,

m = 2.5 kg ; r = 2 m ;

At the bottom of the circle,

T1 - mg = mv2/R

2.5v^2/2 = 49 - 2.5 x 9.8 = 4.5

v = sqrt (4.5 x 2/2.5) = 4.43 m/s

Hence, v = 4.43 m/s

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