a 100kg guy stands frictionless ice facing a 50 kg woman. the woman pushes the g

Question

a 100kg guy stands frictionless ice facing a 50 kg woman. the woman pushes the guy and gives him an acceleration of +2.0m/s^2. What force( magnitude and direction) is applied to the woman? a 100kg guy stands frictionless ice facing a 50 kg woman. the woman pushes the guy and gives him an acceleration of +2.0m/s^2. What force( magnitude and direction) is applied to the woman? a 100kg guy stands frictionless ice facing a 50 kg woman. the woman pushes the guy and gives him an acceleration of +2.0m/s^2. What force( magnitude and direction) is applied to the woman?

Explanation / Answer

we know that force on a mass

Fnet = mxa

a= 2m/s^2

m = 100kg

Fnet = 200N

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