#11 RI 1.111 85% 191 8 PM My Notes Ask Your Teacher The system shown in the figu
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#11
RI 1.111 85% 191 8 PM My Notes Ask Your Teacher The system shown in the figure below has an acceleration of magnitude 0.97 m/s2, where m1 = 4.50 kg and m2 = 8.70 kg. Assume that the coefficient of kinetic friction between block and incline is the same for both inclines. 35.0 S5.0 (a) Find the coefficient of kinetic friction. Your response differs from the correct answer by more than 1 00%. (b) Find the tension in the string. Your response differs from the correct answer by more than 10%. Double check your calculations. N Need Help? ReadExplanation / Answer
sin 35° = 0.574
cos 35° = 0.819
g = 9.80 m/sec^2
motive force Fm = m2*g*sin 35 = 0.574*m2*g
opponent force Fo = m1*g*sin 35 = 0.574*m1*g
friction force Ff = g(m1+m2)*cos 35* = 0.819*(m1+m2)*g*
(a)
acceleration a :
a = (Fm-(Fo+Ff))/(m1+m2) = g(0.574*m2-0.574*m1-0.819*(m1+m2)*)
0.97 = 9.8(0.574(8.70)-0.574(4.50)-0.819(13.20))
105.95 =48.94-25.313-0.97
friction coefficient = 22.66/105.95 = 0.214
(b)
tension T = m1*g*(sin 35°+cos35*) = 4.5*9.8*(0.574+0.819*0.214) = 33.04 N
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