5. A long solenoid of radius 2.5cm current length. A smaller coil of 15 turns an

Question

5. A long solenoid of radius 2.5cm current length. A smaller coil of 15 turns and 1.0cm a) Calculate the magnetic p b) Calculate the m receive maximum flux? c) If voltage in the coil? d) What is the i 5.0A in 0.1 second? cm carries current of 2.5A. It has 35 turns per centimeter roduced inside the shas, is radius is placed inside the solenoid. field produced inside the solenoid. t the smaller coil has. How is the smaller coil placed to ecurrent in the soleno id is cut-off in 0.1 second, what is the maximum induced nduced voltage in the coil if, instead, the current increases fronm

Explanation / Answer

Here ,

a) magnetic field inside = u0 * n * I/L

magnetic field inside = 4pi*10^-7* 3500 * 2.5

magnetic field inside = 0.011 T

the magnetic field inside is 0.011 T

b)

maximum flux in smaller coil = magnetic field * area

maximum flux in smaller coil = 0.011 * pi * 15 * 0.01^2

maximum flux in smaller coil = 5.18 *10^-5 T.m^2

c)

maximum induced voltage = change in flux/time

maximum induced voltage = ( 5.18 *10^-5- 0)/0.1

maximum induced voltage = 5.18 *10^-4 V

d)

maximum induced voltage = change in flux/time

maximum induced voltage = ( 5.18 *10^-5) * (2 -1)/0.1

maximum induced voltage = 5.18 *10^-4 V

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