The times spent waiting in line by all drivers to get their licenses renewed at
ID: 3290082 • Letter: T
Question
The times spent waiting in line by all drivers to get their licenses renewed at the motor vehicle department office of a large city have a distribution that is skewed to the right with a mean of 24 minutes and a standard deviation of 7 minutes.
Calculate the mean and standard deviation of x and comment on its shape of its sampling distribution and why its isthat shape.
Find the probability that the mean waiting time for a random sample of 100 drivers to get their licenses renewed is:
a. less than 22 minutes
b. between 23-26 minutes
c. within 2 minutes of population mean
d. greater than the population mean by 4 minutes
Explanation / Answer
for n=100 ; mean =24
std deviation of mean =7/(100)1/2 =0.7
ffor sample size is greater then 30 ; therefore as per central limit theorum shape of the distribution will be normal.
a) P(X<22) =P(Z<(22-24)/0.7)=P(Z<-2.8571)=0.0021
b)P(23<X<26)=P(-1.4286<Z<2.8571)=0.9979-0.0766 =0.9213
c)P(22<X<26)= P(-2.8571<Z<2.8571)=0.9979-0.0021 =0.9957
d)P(X>28)=1-P(X<28)=1-P(Z<5.7143)=1-~1 =0.0000
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