Question
I don' know who to do questions number 2 in the first exercise and the last one question in the second exercise .
3. A manufactured component has its quality graded on its performance, appe ured component has its quality graded on its performance, appearance, and cost. Each of these three characteristics is graded as either pass or fail probabili . There is a ty of 0.40 that a component passes on both appearance and cost. There is a probability of 0.31 that a component passes on all three characteristics. There is a probability of 0.64 that a component passes on performance. There is a probability of 0. 19 that a component fails on all three characteristics. There is a probability of 0.06 that aA component passes on appearance but fails on both performance and a. Define the events. A, A2 What is the probability that a component passes on cost but fails on both performance and appearance? wnns egatios What stheprobabilty hiata cmone on both performance b. -pl ): 0 36A'I ( .se (0K) () _ (o 36x0%) (0 36 x 03)- bahy035+(03Sv0KvD3) 0, 04731 v07 oc c. "If a component passes on both appearance and cost, what is the probability that it v/ A passes on all three characteristics? 4. A salesman has to visit 10 different cities. Inhow many differen of the visits be made? If he decides that 5 of the visits will be made one week, and the other 5 will be made the following week, in how many different ways can the 10 cities be split into two groups of 5 cities? ID 1 - A 06 nor co… o6 o S 5140 0732 + 1S eek vov have lD le Page 2 of 2 Lol
Explanation / Answer
question number 2 means b part and last question is 4 ok here are the solutins
b)What is the probability that a component passes on cost but fails on both performanceand appearance?
Pr(A C P )'=Pr(A C) -Pr(A C P )=0.40 -0.31 = 0.09
IF YOU WANT IN YOUR NOTATION REPRESENT A C P IN A1 A2 A3
4) A sales man has to visit 10 different cities
number of different ways of ordering = 10!
now he will will 5 in one week from 10 = 10C5
another 5 he will in another week = 10c5
number of ways =10c5+10c5= 252+252 =504
