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I conducted a Paired T-Test for my upcoming Psychology Research Paper. The Alpha

ID: 3291685 • Letter: I

Question

I conducted a Paired T-Test for my upcoming Psychology Research Paper. The Alpha was 0.05. My Study is Reaction Time, one group using peppermint one not using peppermint. My Mean w/Peppermint was 0.39 and w/out Peppermint was 1.1. My P answer came back at 7.354641 can you help to explain my results? It is higher than 0.05? I can conduct the tests using excel but have a very hard time explaining them. Thank you. I posted the results from excel. This has been answered for me, but I did not make it clear that this was a paired t-test using the same subjects for both sides. I hope that helps. I need help explaining this as I don't understand how to put the results in "laymans" terms.

t-Test: Two-Sample Assuming Unequal Variances Reaction Time w/Peppermint Reaction Time w/out Mean 0.39 1.1 Variance 0.110005139 1.445268749 Observations 80 80 Hypothesized Mean Difference 0 df 91 t Stat -5.321101689 P(T<=t) one-tail 3.67732E-07 t Critical one-tail 1.661771155 P(T<=t) two-tail 7.35E-07 Alpha 0.05 t Critical two-tail 1.986377154

Explanation / Answer

If we take it as a one tail test then p value in table is = 3.67732E-07 which is less then 0.05 (alpha)

Remember this:

A small p-value (typically 0.05) indicates strong evidence against the null hypothesis, so you reject the null hypothesis.

So, here too we reject the null hypothesis.

Even if it is a two tail p value 7.35E-07 is less then 0.05 and thus null is rejected.

This means reaction times with and without peppermint are different.

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