I\'M NOT SURE IF I AM DOING THIS PROBLEM CORRECTLY. PART OF IT IS LEFT BLANK BEC

Question

I'M NOT SURE IF I AM DOING THIS PROBLEM CORRECTLY. PART OF IT IS LEFT BLANK BECAUSE I'M STUCK.

Doggie Nuggets Inc. (DNI) sells large bags of dog food to warehouse clubs. DNI uses an automatic filling process to fill the bags. Weights of the filled bags are approximately normally distributed with a mean of 66 kilograms and a standard deviation of 1.07 kilograms. Complete parts a through d below. a. What is the probability that a filled bag will weigh less than 65.9 kilograms? The probability is4641 (Round to four decimal places as needed.) b. What is the probability that a randomly sampled filled bag will weigh between 64.5 and 67 kilograms? The probability is 7431 (Round to four decimal places as needed.) C. What is the minimum weight a bag of dog food could be and remain in the top 21% of all bags filed? The minimum weight iskilograms (Round to three decimal places as needed.) d. D is unable to ad ust the mean of the 1 ng process. However, t s able to ad ust the standard deviation of the filing process hat o h standard deviation needtob s that no more than 6% all filed a swel more than 70 kilograms? The standard deviation would need to be kilograms (Round to three decimal places as needed.)

Explanation / Answer

c)

P(X > x) = 0.21

=>

x - 56 / 1.07 = invnorm(1-0.21)

=>

x = 1.07 * 0.806 + 56

= 56.862

d)

P(X >x) = 0.06

=>

P(Z >70-56/s) = 0.06

=>

70-56/s = invnorm(1-0.06)

s = (70-56)/1.555

= 9.003

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