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Need help with questions 17 and 7 only 17) the statistics course. Assume that 20

ID: 3301411 • Letter: N

Question

Need help with questions 17 and 7 only
17) the statistics course. Assume that 20 students registered for the course. a. Compute the probability that 2 or fewer will withdraw b. Compute the probability that exactly 4 will withdraw c. Compute the probability that more than 3 will withdraw. 18) What is the probability of creating a 4-digit pin with no repeating numbers? 19) Flights approaching major airports in the US during peak hours often experience elays in landing due to air traffic congestion. You will often ear announcements from the ilot that sound like this - "... we expect to land at 5:25PM bject to air traffic delays" ssume that flights flying in to an airport during peak hours are ibject to delays that are niformly distributed between 10 and 45 minutes. [Be sure to ow your calculations for arts (b) through (f).] a. Draw the probability distribution of air traffic delay b. What is the probability that a flightl have an air traffic delay of less than 9 minutes? c. What is the expected value of air traffic delay? d. What is the standard deviation of air traffic delay? e. What is the probability that a flight will be delayed between 30 and 40 minutes? f. What is the probability a flight wl be delayed more than 50 minutes? 20) An individual wants to fly from Washington's Dulles airport, stopover in Amsterdam to visit a friend and then fly on to Prague. Of the 15 airlines that fly from Washington to msterdam, 10 are members of the Star Alliance network. Of e 10 airlines that fly from Amsterdam to Prague, 6 are embers of Star Alliance. What is the likelihood that at least ne of the segments will be on a Star Alliance partner airline?

Explanation / Answer

Ans:

17)Binomial distribution

n=20

probability of withdrawing,p=0.2

a)Probabilty that 2 or fewer will withdraw

P(k<=2)=20C0*(0.2)0*(0.8)20+20C1*(0.2)1*(0.8)19+20C2*(0.2)2*(0.2)18

using Excel function:

P(k<=2)=BINOMDIST(2,20,0.2,TRUE)=0.2061

b)P(k=4)=20C4*(0.2)4*(0.8)16

P(k=4)=BINOMDIST(4,20,0.2,FALSE)=0.2182

c)P(k>3)=1-P(k<=3)

P(k>3)=1-BINOMDIST(3,20,0.2,TRUE)=0.5886

d)Expected number of withdrawals=np=20*0.2=4

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