conducted a survey of citizens over 60 whose net wo but who have no private heal
ID: 3302555 • Letter: C
Question
conducted a survey of citizens over 60 whose net wo but who have no private health insurance. The ages of 25 uninsured ssues are receiving much attention in both academic and political arenas o years of age whose net worth is too high to qualify for government A sociologist recently health care 68 73 66 76 86 74 61 89 65 90 69 92 76 62 81 63 68 81 70 73 60 87 75 64 82 senior citizens were as follows uppose the mean and st s bell Shaped, what percentage of the respondents will be between 64.3 and 93,4 years tandard deviation are 74.0 and 9.7, respectively. If we assume that the distribution of ag e chole data. Find any outliers. esterol levels (in milligrams per deciliter) of 30 adults are listed below. Draw a boxplot that represen 154 156 165 165 170 171 172 180 184 18 189 189 190 192 195 198 198 200 200 200 205 205 211 215 220 220 225 238 255 275 The scores from a state standardized test have a bell-shaped distribution with a mean of 100 and a st of 15. Use the Empirical Rule to find the percentage of students with scores between 70 and 130Explanation / Answer
We first get the z score for the two values. As z = (x - u) / s, then as
x1 = lower bound = 64.3
x2 = upper bound = 93.4
u = mean = 74
s = standard deviation = 9.7
Thus, the two z scores are
z1 = lower z score = (x1 - u)/s = -1
z2 = upper z score = (x2 - u) / s = 2
Using table/technology, the left tailed areas between these z scores is
P(z < z1) = 0.158655254
P(z < z2) = 0.977249868
Thus, the area between them, by subtracting these areas, is
P(z1 < z < z2) = 0.818594 = 81.8%
[ANSWER: A: 81.5%, CLOSEST]
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Note that the difference could be due to round off error. The answer above is exact.
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