Five data entry operators work at the data processing department of the Birmingh
ID: 3306255 • Letter: F
Question
Five data entry operators work at the data processing department of the Birmingham Bank. Each day for 30 days, the number of defective records in a sample of 300300 records typed by these operators has been noted, as follows: Sample No. No. Defectives Sample No. No. Defectives Sample No. No. Defectives 1 88 11 66 21 1717 2 44 12 66 22 1212 3 1818 13 1616 23 55 4 1010 14 55 24 88 5 1111 15 1111 25 1414 6 88 16 77 26 1111 7 1313 17 1212 27 1515 8 1010 18 55 28 66 9 77 19 1919 29 1111 10 1313 20 1717 30 22 a) Establish 3sigma upper and lower control limits. UCL Subscript p UCLp = nothing (enter your response as a number between 0 and 1, rounded to three decimal places). Five data entry operators work at the data processing department of the Birmingham Bank. Each day for 30 days, the number of defective records in a sample of 300300 records typed by these operators has been noted, as follows: 300300 Sample No. No. Defectives Sample No. No. Defectives Sample No. No. Defectives 1 88 11 66 21 1717 2 44 12 66 22 1212 3 1818 13 1616 23 55 4 1010 14 55 24 88 5 1111 15 1111 25 1414 6 88 16 77 26 1111 7 1313 17 1212 27 1515 8 1010 18 55 28 66 9 77 19 1919 29 1111 10 1313 20 1717 30 22 Sample No. No. Defectives Sample No. No. Defectives Sample No. No. Defectives 1 88 11 66 21 1717 2 44 12 66 22 1212 3 1818 13 1616 23 55 4 1010 14 55 24 88 5 1111 15 1111 25 1414 6 88 16 77 26 1111 7 1313 17 1212 27 1515 8 1010 18 55 28 66 9 77 19 1919 29 1111 10 1313 20 1717 30 22 a) Establish 3sigma upper and lower control limits. 3sigma UCL Subscript p UCLp = nothing (enter your response as a number between 0 and 1, rounded to three decimal places). UCL Subscript p UCLp nothing Sample No. No. Defectives Sample No. No. Defectives Sample No. No. Defectives 1 88 11 66 21 1717 2 44 12 66 22 1212 3 1818 13 1616 23 55 4 1010 14 55 24 88 5 1111 15 1111 25 1414 6 88 16 77 26 1111 7 1313 17 1212 27 1515 8 1010 18 55 28 66 9 77 19 1919 29 1111 10 1313 20 1717 30 22Explanation / Answer
total number of defects =307
total number of sample =300*30=9000
proportion of defects p =307/9000 =0.034
std error =(p(1-p)/n)1/2 =0.0105
hence UCL = p+3*std error =0.066
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.