Biostats Quiz: Ch.5 Please do not write on this sheet *\"Turn in answers ONLY. d
ID: 3306467 • Letter: B
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Biostats Quiz: Ch.5 Please do not write on this sheet *"Turn in answers ONLY. do not need to see your work For Binomial problems, tell me how you would get the answer with Lane's calculator. Thus, provide R, N, and either Above #, Below #, or Between # and #. Present answers as fractions or decimals rounded off to three digits after the decimal point. A box contains 5 black pieces of cloth, 3 striped pieces, and 7 dotted pieces. A piece is selected randomly and then placed back in the box. A second piece is selected randomly. What is the probability that a. both pieces are dotted? b. the first piece is black and the second piece is dotted? c. one piece is black and one piece is striped? You draw three cards from a deck without replacement. What is the probability of drawing three aces? when Susan and Jessica play a card game, Susan wins 65% of the time. If they play 25 games, what is the probability that Jessica will have won more games than Susan? 1. 2. 3, 4. You roll a fair die five times, and you get a 6 each time. What is the probability that you get a 6 on the next roll? If you role a six-sided die, what is the probability of rolling a 4,5, or 6? If you role 2 dice, what is the probability that at least one of them will be 6? On average, the fire department receives about 1 call per week. However, during the week of Halloween, it received 5 calls. You want to know how probable 5 calls are given that usually there's only 1 per week. What type of distribution should you use for this problem? An entomologist spots what might be a rare subspecies of beetle, due to the pattern on its back. In the rare subspecies, 94% have the pattern. In the common subspecies, 11% have the pattern. The rare subspecies accounts for only 0.5% of the population. How likely is the beetle having the pattern to be the rare subspecies? 5. 6. 7. 8.Explanation / Answer
since the piece is replaced, probabilities will remain unaltered P[black] =5/15=1/3
P[striped] = 3/15=1/5
P[dotted] = 7/15
A) P[both dotted]
= 7/15*7/15 =49/225
B) P[1st black,2nd dotted]
= 1/3 * 7/15
= 7/45
C)
P[black-striped] + P[striped-black]
= 1/3 * 3/15 + 3/15* 1/3
=6/45
=2/15
2) 4/52*3/52*2/52
3)
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