Number 2. I think the answer is a c g and h because to have acceleration not equ

Question

Number 2. I think the answer is a c g and h because to have acceleration not equal to zero there must be a speeding up, slowing down or Chang of direction. I assumed that moving around a curve would be a change in direction. So any constant values would be thrown out. B I'm not sure of notation

DTimtt Vectors cuton PHY 251: Master Set: Ch. 02 One-Dimensional Motion 1. Under what condition will a motion problem require the use of calculus to solve? Geins from elar-l direction Definitions and Basics-7 Which ofthe following would be an indication of an object undergoing an? a) changing direction cmoving around a curve b) jerk, d, is not 2. f) not moving d) moving at a constant speed g) slowing down e) moving at a constant velocity h) speeding up 3. A box is slid along a level frictionless floor to the right and then up a frictionless ramp. The box reaches a certain point on the ramp when it naturally turns around, slides back down ramn to the level floor until it hits a wall. Assume that the position - 0 just after the th transit

Explanation / Answer

According to the given problem,

2.)

a) Changing direction - accelarating [a not 0]

Reason: In unifrom circular motion experiences either a change in the magnitude or the direction of the velocity vector can be said to be accelerating

b) Jerk - accelarating [a not 0]

Reason:It is clearly specified a is not 0 in the option itself.

c) Moving around a curve - accelarationg [a not 0]

Reason: An object mogin in a curve will experience a inward accelaration due to change in direction of velocity that is centripetal acceleration.

d) Constant speed - accelarating [a not 0]

Reason: At a constant speed (meaning no change in the magnitude of the velocity) an object could be changing its direction, and thus, accelerating.

g, h) Slowing down, speeding up - accelarating [a not 0]

So, the answer is -[ a,b,c,d,g,h.]

But in e option a constant velocity means no change in velocity (both magnitude and direction), so in this case the acceleration must be zero (no acceleration).

I hope you understood the problem, If yes rate me! or else comment for a better solution.

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