ust49wa.theexpertta.com Class Management i Help Practice 8 Begin Date: 1/1/2018
ID: 3308515 • Letter: U
Question
ust49wa.theexpertta.com Class Management i Help Practice 8 Begin Date: 1/1/2018 12:00:00 AM -- Due Date: 2/20/2018 11:59:00 PM End Date: 3/12/2018 11:59:00 PM (14%) Problem 3: Calculate the maximum acceleration of a car that is heading up a 5.5° slope (one that makes an angle of 5.5° with the horizontal and assuming up the slope is the positive direction) under the following road conditions. Assume that the System Rubber on dry concrete Rubber on wet concrete Steel on steel(dry) Steel on steel (oiled) Shoes on wood Static friction Kinetic friction 0.7 0.5 0.3 0.03 car has four-wheel drive and that the cocfficient of static friction is involved-that is, the tires are not allowed to slip during the acceleration. 0.7 0.6 0.05 0.9 Randomized Variables 0 5.5 Assignment Status Shoes on ice 0.05 Click here for detailed view Steel on ice 0.4 0,02 Problem Status Otheexpertta.com 33% Part (a) Calculate the maximum acceleration of the car on dry concrete in m/s Completed Partial Grade Summary amax393 1% 99% Potential 7 8 9 HOME Submissions Attempts remaining: 9 (1 % per attempt) detailed view sin0 cosO cotan0 asin) acosO atan acotan sinh coshO tanh cotanhO Degrees Radians tan() | 1 23 - 1% 0 END BACKSPACE DEL CLEAR Hint I give up! Hints: 0% deduction per hint. Hints remaining: 3. Feedback: 0% deduction per feedback. 33% Part (b) Calculate the maximum acceleration of the car on wet concrete in m/s 33% Part (c) Calculate the maxinum acceleration of the car on ice in m/s2, assuming that = 0.100 , the same as for shoes on ice All contcat 2018 Eapert TA. LLCExplanation / Answer
perpendicular to the incline,
N - m g cos5.5 = 0
N = m g cos5.5
and fs = us N = us m g cos5.5
along the incline,
Fnet = fs - m g sin5.5 = m a
a = us g cos5.5 - g sin5.5
(A) us = 1
a = 9.8 (cos5.5 - sin5.5) = 8.82 m/s^2
(B) us = 0.7
a = 5.9 m/s^2
(C) us = 0.10
a = 0.036 m/s^2
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