I am struggling with using Kirchhoff\'s rule in circuits with Inductors. Looks l

Question

I am struggling with using Kirchhoff's rule in circuits with Inductors. Looks like if you have an inductor, we have Electric field (E) that is created using a time varying magnetic field and that E is non conservative and hence you will have to use Faraday's and not Kirchoff's rule. I get that. But when you use Faraday's rule, Electric field within inductor is taken to be zero as it has zero resistance. I dont get the connection of zero resistance and zero electric field. why electric field is zero in an inductor.?

Below is link where Prof Lewin uses Faraday's law. I get everything in this video other than why E should be zero within the inductor

https://www.youtube.com/watch?v=cZN0AyNR4Kw

Explanation / Answer

Ideal self inductor is made up of superconducting wires. By superconducting wire we must know that it will have zero resistance. Now since there is no resistance to offer, current in the wires of the inductor flows constantly, i.e there is no variation in the current with time. Now magnetic field inside a inductor (which is a solenoid) is given by -

H=n*i , where n are no of turns in the solenoid and i is the current in the wires of the inductor.

Electric field inside the solenoid is induced by the change in magnetic flux. Since there is no change in current with time, there will be no change in H with time. therefore, no electric field is induced inside the solenoid.

Hence, inside the inductor the Electric field is zero.

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.