Responses tastdep 18132748 As a engineer, you are designing a heat pump that is

Question

Responses tastdep 18132748 As a engineer, you are designing a heat pump that is capable of delivering heat at the rate of 18 kw to a house. The house is located where, in January, the average temperature is 10°C. The temperature of the air in the air handler inside the house is to be 43°C. (a) What is the maximum Cop for a heat pump operating between these temperatures? b) What must be the minimum power of the electric motor driving the heat pump be? (e) In reaity, the COP of the heat pump will only be 60 percent of the ideal value. What is the minimum power of the electric motor when the COP is 60 percent of the ideal value? kw Use the definition of the COPue and the Carnot efficiency of an engine to express the maximum efficiency of the refrigerator in terms of the reservoir temperatures. Apply the deofinition of power to find the minimum power needed to run the heat pump 010 points 1 Previous Answers Tipler 19 P 051 A refrigerator is rated at 426 w iMy Notes O Ask Your Teachs (a) what is the maximum amount of heat it can absorb from the food compartment in 1.00 min if the temperature in the 35 C7 0 166 compartment is o.onc and it releases heat into a room at b If he COP of the refrigerator is 70% of that of a reversible refrigerator, how much heat can t absorb from the food compartment in 100 mi ? Type here to search

Explanation / Answer

Problem 7)

The rate of heat delivering to the house P = 18 kW

the tempertures are Tc = -10 C or 263 K and Th = 43 C or 316 K

(a) The maximum COP for a heat pump operating between Tc and Th

COP = Qh/W

= Th/Th - Tc

= (316) / [ 316-263]

= 5.96

(b) The power, P' = W/t

The work done by heat engine W = Qh /COP

then Power P' = (Qh/COP) / t

= (P)/COP

= 18 kW/5.96

= 3.02 kW

(c) The minium power of the motor when COP is 60%

P min = (Qh/COP)/t

= 18 kW / (0.6)(5.96)

= 5.03 kW

According to chegg guidelines i can answer one question at a time so please post other questions seperately.

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