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Review the output to answer the following questions: a. Identify the IV & DV b.

ID: 3309828 • Letter: R

Question

Review the output to answer the following questions:

a. Identify the IV & DV

b. State the H0& H1.

c. What is the regression equation based on the information present in the output?

d. Based on your review of the output, do you accept or reject the null hypothesis? Explain why you decided to either reject or fail to reject the null hypothesis. (Note: You do not have to perform the 5 step hypothesis testing method. Just interpret what is on the output).

e. If you reject the null hypothesis, please interpret the slope.

f. If the slope is significant, how strong is its effect?

g. Based on the results of the analysis, how much does the IV explain the DV?

Model Summary Adjusted R Square Std. Error of the Estimate Model R Square 249a 062 .072 91434 a. Predictors: (Constant), Number of crimes solved ANOVAa Sum of Squares df Mean Square 386 836 Model Sig Regression Residual Tota 386 5.852 6.238 462 518 a. Dependent Variable: Violent crime rate b. Predictors: (Constant), Number of crimes solved Coefficientsa Standardized Unstandardized Coefficients Coefficients Model Std. Error Beta Sig (Constant) Number of crimes solved 3.332 073 1.835 .680 6.114 109 .050 ,249 518 a. Dependent Variable: Violent crime rate

Explanation / Answer

a) IV: Number of crimes solved

DV: Violent Crime Rate

b) Ho: Number of crime solved is a good predictor the Violent crime rate.

Ha: Number of crime solved is not a good predictor the Violent crime rate.

c) Regression Equation:

y = 6.114 - 0.050 x

d) From the ANOVA table, p - value = 0.518

Since this value is very high, we do not reject Ho

e) We do not reject the null hypothesis so the meaning of slope will not be applicable in this context.

f) The slope is not significant.

g) R2 = 0.062

Hence,

Only 6.2% of the variation in DV can be explained by IV.

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