t polit A matched pairs experiment is carried out, yielding the following data:
ID: 3312405 • Letter: T
Question
t polit A matched pairs experiment is carried out, yielding the following data: nD = 69, XD =-2.4 , SD = 7.9 Is there evidence, at an = 0.06 level of significance, to conclude that there is a difference between the two sets of measurements? Carry out an appropriate hypothesis test,filing in the information requested. A. The value of the standardized test statistic: -2.52 Note: For the next part, your answer should use interval notation. An answer of the form (-co, a) is expressed (-infty, a), an answer of the form (b, oo) is expressed (b, infty), and an answer of the form (-0o, a) U (b, oo) is expressed (-infty a)U(b, infty) B. The rejection region for the standardized test statistic C. The p-value is D. Your decision for the hypothesis test: A. Do Not Reject Hi B. Reject Hi c. Reject Ho D. Do Not Reject Ho-Explanation / Answer
Ans:
a)test statistic:
t=(-2.4-0)/(7.9/sqrt(69))=-2.52
b)df=69-1=68
alpha=0.06
critical t values=TINV(0.06,68)=+/-1.91
Reject H0,if t<-1.91 or t>1.91
(-infinity,-1.91) or (1.91,+infinity)
c)
p-value=TDIST(2.52,68,2)=0.0140
d)As,p-value<0.06,we reject null hypothesis,H0.
Option C is correct.
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