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1) 1. You are interested in determining the difference in two population means.

ID: 3314643 • Letter: 1

Question

1)

1.     You are interested in determining the difference in two population means. You select a random sample of eight items from the first population and eight from the second population and then compute a 95% confidence interval. The sample from the first population has an average of 12.2 and a standard deviation of 0.8. The sample from the second population has an average of 11.7 and a standard deviation of 1.0. Assume that the values are normally distributed in each population. The point estimate for the difference in means of these two populations is ______.

-0.2

0.2

0.5

-0.5

0.06

2)

1.     A researcher wishes to determine the difference in two population means. To do this, she randomly samples nine items from each population and computes a 90% confidence interval. The sample from the first population produces a mean of 780 with a standard deviation of 240. The sample from the second population produces a mean of 890 with a standard deviation of 280. Assume that the values are normally distributed in each population and that the population variances are approximately equal. The critical t value used from the table for this is

1.860

1.734

1.746

1.337

2.342

-0.2

0.2

0.5

-0.5

0.06

2)

1.     A researcher wishes to determine the difference in two population means. To do this, she randomly samples nine items from each population and computes a 90% confidence interval. The sample from the first population produces a mean of 780 with a standard deviation of 240. The sample from the second population produces a mean of 890 with a standard deviation of 280. Assume that the values are normally distributed in each population and that the population variances are approximately equal. The critical t value used from the table for this is

1.860

1.734

1.746

1.337

2.342

Explanation / Answer

1. point estimate for differences between means

= First sample mean - Second sample mean

= 12.2 - 11.7

= 0.5

Option C is correct.

2. Degrees of freedom = n1 + n2 - 2 = 9 + 9 - 2 = 16

Hence,

Critical t value = 1.746

Option C is correct.