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Can you help me with question f, g, h i ? Thank you so much! A teacher did a pol

ID: 3317235 • Letter: C

Question

Can you help me with question f, g, h i ? Thank you so much!

A teacher did a poll of the students attending Happy Valley School as to whether the student believed in Santa Claus or not. The results of the poll are summarized in the table below. 4. Believe in Santa Claus GRADE in School Kindergarten 1st Grade 2nd Grade 3rd Grade 4th Grade 5th Grade TOTAL YES 27 27 19 NO TOTAL 2 9 15 31 6 30 78 186 a) b) c) d) e) Fill in the missing values in the table. (3 points) A student is randomly chosen from the sample; what is the probability that the student does not believe in Santa Claus? Is this a joint, marginal, or conditional probability? (3 points) If a second grader is chosen, what is the probability that he/she believes in Santa? Is this a joint, marginal, or conditional probability? (3 points) What is the probability that a randomly chosen student is in 3rd grade and does not believe in Santa? Is this a marginal, joint or conditional probability? Write out the hypotheses for the Chi-Square(2) test of this data Finish the table of expected counts f)

Explanation / Answer

Part a

Completed table is given as below:

Believe in Santa Claus

Grade

Yes

No

Total

Kindergarten

27

2

29

1st

27

6

33

2nd

19

9

28

3rd

16

15

31

4th

13

22

35

5th

6

24

30

Total

108

78

186

Part b

Number of students does not believe in Santa Claus = 78

Total number of students = 186

Required probability = 78/186 = 0.419355

This is a marginal probability.

Part c

Number of students in second grade = 28

Total number of students = 186

Number of 2nd grade students believe in Santa Claus = 19

Required probability = (19/186) / (28/186) = 19/28 = 0.678571

This is a conditional probability.

Part d

Total number of students = 186

Number of students in 3rd grade who does not believe in Santa = 15

Required probability = 15/186 = 0.080645

This is a joint probability.

Part f

We are given a observed frequencies table as below:

Observed Frequencies

Column variable

Yes

No

Total

Kindergarten

27

2

29

1st

27

6

33

2nd

19

9

28

3rd

16

15

31

4th

13

22

35

5th

6

24

30

Total

108

78

186

Now, we have to find expected frequencies. Formula for expected frequencies is given as below:

E = Row total * Column total / Grand total

We are given grand total = 186

By using this formula, table for expected frequencies is given as below:

Expected Frequencies

Column variable

Yes

No

Total

Kindergarten

16.83871

12.16129

29

1st

19.16129

13.83871

33

2nd

16.25806

11.74194

28

3rd

18

13

31

4th

20.32258

14.67742

35

5th

17.41935

12.58065

30

Total

108

78

186

Part g

Formula for partial Chi square values is given as below:

Partial chi square = [(O – E)^2/E)

Where, O is observed frequencies and E is expected frequencies.

Table for partial Chi square is given as below:

Grade

Yes

No

Kindergarten

6.131813

8.490203

1st

3.206745

4.440108

2nd

0.46243

0.640287

3rd

0.222222

0.307692

4th

2.638454

3.653244

5th

7.486022

10.36526

Part h

Chi square test statistic = [(O – E)^2/E) = 48.04448

Number of rows = r = 6

Number of columns = c = 2

Degrees of freedom = (r – 1)*(c – 1) = (6 – 1)*(2 – 1) = 5*1 = 5

Part i

= 0.05

P-value = 0.00 (By using Chi square table or excel)

P-value < = 0.05

So, we reject the null hypothesis that grade and believe in Santa Claus are independent of each other.

There is insufficient evidence to conclude that grade and believe in Santa Claus are independent of each other.

Believe in Santa Claus

Grade

Yes

No

Total

Kindergarten

27

2

29

1st

27

6

33

2nd

19

9

28

3rd

16

15

31

4th

13

22

35

5th

6

24

30

Total

108

78

186

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