I need help answering this. a3· lf the sandard normal deviate of random variable

Question

I need help answering this.

a3· lf the sandard normal deviate of random variable value ofre2 s t--2 while te tandard devimion of the random variable r equals 2, then the tmean of z is A). 6 B). 4 C S E. 0 44. If a sample of n elements is selected from a population of N elenments using a sampling plan in which each of the possible samples has the same chance of being seiected, then the sampimg is d to be randem and the resuliting sample is a simple randomm sample A). Trze B). False 45. The shape of the normal probability distibutien is determined by the population standard deviaion o. Large values of a reduce the height of the curve ard increase the spread: Smal values of s increase the height of the curve and reduce the spread A. Trae B. False 46. A cominuous Tandom variable r ts normally disuributed with a mean of 1200 and a standad deviacion of 150. Given that A). Tne B). False 1510, its corresponding i-score is 1.40. 7. Fora continuous random variable x, the probabilities Ps.c s 0, and P(0

Explanation / Answer

43) mean =x- z*std deviation =2-(-2)*2 =6

option A

44)

option A; true

45)

true

46)

z score=(X-mean)/std deviaiton=(1510-1200)/150=2.067

false

47)

false

48)

area =0.3849+0.4192=0.8041

option B

49)

if option 0.9545 is there than 0.9545 is correct

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.