For part b, i dont get why we are cubing 2/3 and 1/3 when we calculate P(getting
ID: 3318382 • Letter: F
Question
For part b, i dont get why we are cubing 2/3 and 1/3 when we calculate P(getting three red aka 333). Also in the same sense, I don't get why we are squaring 2/3 and 1/3 for the denominator. What distribution and what rule are we using to do that?1. Die A has 4 red and 2 white faces, whereas die B has 2 red and 4 white faces. A fair coin is flipped once. If it lands on heads, the game continues with die A: if it lands tails, then die B is to be used. a) What is the probability of red at any throw? b) If the first two throws result in red, what is the probability of red at the third throw? c) If red turns up at the first two throws, what is the probability that it is die A that is being used? Solution 14 12 1 row n is red) =--+--=- 26 26 2 12 (1 23) 2 3 1 (2 2 3 1(2)2.1(1)2 2(3) 2 3, c)P(Al rr) = P(rr1A)P(A) 5
Explanation / Answer
as given in question coin is only flipped once if head comes the whole process is continued with die A and if tail comes then whole process is continued with die B.
what you are asking is applicable if coin is flipped every time before throwing of die but in our question coin is flipped only once ( so probability of head or tail is 1/2) and after that process is continued without again flipping the coin with either die A or die B.
if you still have any doubt regarding solution please comment here.
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