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Chapter 10, Section 1, Exercige 002 The leg\'essan equal:an Y = 42.4-6.92X 1 1 .

ID: 3319896 • Letter: C

Question

Chapter 10, Section 1, Exercige 002 The leg'essan equal:an Y = 42.4-6.92X 1 1 .67X2 + 1 .53X3 0.42 1 X4. Cael SE Cae 42.41 18.36 2.31 0.060 -6,922 1.075-6.44 0.001 Canslan X1 X2 X3 X4 1.670 .168 143 0.202 15281 0.5400 2.83 0.030 0.4212 0.1399 3.01 0.024 S = 2.04939 R-Sq = 99.8% R-Sq (adj) = 99.6% DF MS 4 11033.2 2758.3 650.66 0.000 6 25.2 4.2 Regiearn Talal 10 11058.4 One case in lhe sample has Y = 33. X1 7. X2 6, X3 6, and X4 52. wnal s lhe pied clea espanse la Inc case, wrnal s lhe esaudP Raund yaul answeis la ane decimal place 2.D Piedcled iespa n2e 25.2 Resdual:

Explanation / Answer

Regression equation :

Predicted Y = 42.4 - 6.92X1 + 1.67X2 + 1.53X3 + 0.421X4

Given,

Y=33 , X1=7, X2=6, X3=6, X4=52

Predicted Y = 42.4 - 6.92 x 7 +1.67 x 6 + 1.53 x 6 + 0.421 x 52 = 42.4 - 48.44 + 10.02 + 9.18 + 21.892 = 35.052

Predicted response = 35.052

Residual = Actual - Predicted = 33 - 35.052 =-2.052

Residual = -2.052

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