Resourc × \\ :: Grades. Elementary Sta· x\\Mail. CTSCHI3824@unc x/D PracticeFina

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Resourc × :: Grades. Elementary Sta· xMail. CTSCHI3824@unc x/D PracticeFinal oads/PracticeFinal%20(1).pdf wus9 Current Student Res.STATS D cengage H http://www.netflix.co Short Answer (5pts each): I. Given a 5 x 4 matrix for a . test, what would dr = 2. Given a ratio of 1:2:2 and observed values of 22, 45, and 33, what would be the three expected values? 3. What is the smallest possible value? 4, All the elements in a need to be greater than what value? 5. When testing the linear regression, what is the df when n- 6. When the slope of a line is 0, what must also be 0? 7. If I am comparing 3 means, what would be the difactor) for the ANOVA test? 8. If dir factor)- 4 and SS(factor)- 120, what does the MS(factor)-? 9. If'MS(tactor) 30 and MStertor)-6, what does F- 10. What is the shape of the F- distribution?

Explanation / Answer

(1)

Degree of freedom df = (r-1)*(c-1)

= (5-1)*(4-1)

= 12

Hence, df=12.

(2)

Observed Values O:

22

45

33

100

=SUM(F3:H3)

Ratio:

1

2

2

5

Expected Values E =

20

40

40

100

=I3*F4/I4

(3)

The smallest possible chi-square value is zero, but, no upper bound; it depends on the size of the numbers.

(4)

  All the elements in a chi-square need to be greater than 5.

  The notion of Chi-squire testing is not that the value observed in each cell is more than 5. It is that the expected value in each cell is greater than 5.

Observed Values O:

22

45

33

100

=SUM(F3:H3)

Ratio:

1

2

2

5

Expected Values E =

20

40

40

100

=I3*F4/I4

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