16. The probability that an observation taken from a standard normal population
ID: 3323833 • Letter: 1
Question
16. The probability that an observation taken from a standard normal population will have a z value less than 2 and greater than T 1.5, ie, n.1.5;2,is: A. 5896 B. 4104 C. .0896 D. .9104 17 A random sample of 100 observations is taken from a normal population where the standard deviation is 10. The sample mean is 30 sample mean is: The 95% confidence interval for the A. 28.36 to 31.65 B. 28.04 to 31.96 C. 20.00 to 40.00 D. 21.76 to 38.24 18. The following sample is taken to estimate the average age of people in a local community 50, 43, 65, 52, 45, 60, 28, 62, 53 The mean of these data is 50.89. Assume a normal distribution with a standard deviation of 10, The upper bound for a 90% confidence interval for the population mean is A. 45.41 B. 57.42 C. 56.37 D. 54.3 Use the following information to answer questions #19 through #21 : To determine if their 12 oz. filling machine is properly adjusted, Jackson Soft Drinks has decided to use an -Chart and an R Chart. The samples of size n-4 are shown in the table below. Sample 9 Averages Sample Mean 12.01 12 1197 195 11.99 12.05 11.98 11.97 1196 11.9867 Sample Range 0.08 0.08 0.09 0.06 0.08 0.04 0.05 0.04 0.02 0.06 19. What is the Center Line of the x-bar control chart? A. 11.925 B. 12.048 -C. 11.9867 D. 0.06Explanation / Answer
Solution:-
16) option D. 0.9104
Explanation:- P(1.5 < Z <2) = P(2) - P(-1.5) = 0.9772 - 0.0668 = 0.9104
17) option:- B. 28.04 to 31.96
Explanation:- X +/- Z * s/sqrt(n) = 30 +/- 1.96*10/sqrt(100) = (28.04 , 31.96)
18) option:- C. 56.37
Explanation:- X + Z * s/sqrt(n) = 50.89 + 1.645*10/sqrt(9) = 56.3733
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