Test-Charles price-Microsoft Edge mathod.com/Student)PayerTestasptestd 166907529

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Test-Charles price-Microsoft Edge mathod.com/Student)PayerTestasptestd 166907529 yes Math 119 Mesa College Fal 2017 k Chanes price 12/15/174:15 uiz: Quiz # 7 ( Ch 9 ) Submit C is Question: 1 pt 5 of 6 This Quiz: 6 pts poss that the two samples are independent simple random samples selected from normaly distributed populations, andn do not assume that the population standard deviations are equal Complete parts (a) and (b) below 36 36 131 25 mm 504 mm Use a 0 01 sigiicance level, and test the dain that the mean skuA treadth in 4000 B C is less than the mean skul' breadth in AD 150. What are the nul and ahemative hypotheses? Thetest suhitis(Round to two dedinal places as needed The P.value isRound to treee decimal places as needed) State the conclusion for the test OA. Fall s ject the nut hpothes There wuflient evidence to support he dain thuit the mean shul breadth was les in 4000 BC than AD. 150 O B. Fal to reject the mul hypotheshs. There is not sufticlent evidence to support the claim that the mean skull breadth was less in 4000 B C than AD 150 C. Repot te ma hypothesis There is not sultiert midence to support te dan' that te mean sha treadth was less in 4000 BCthan AD150. O D. Rejgect the aull hypothesis There is suicient evkoence to sugpont the claim tha the mean skull reaath was less ih 4000 B.C han AD. 159 Click to select your answers) acer

Explanation / Answer

Solution:-

State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.

Null hypothesis: 4000BC> AD150
Alternative hypothesis: 4000BC < AD150

Note that these hypotheses constitute a one-tailed test. The null hypothesis will be rejected if the mean difference between sample means is too small.

Formulate an analysis plan. For this analysis, the significance level is 0.01. Using sample data, we will conduct a two-sample z-test of the null hypothesis.

Analyze sample data. Using sample data, we compute the standard error (SE), z statistic test statistic (z).

SE = sqrt[(s12/n1) + (s22/n2)]
SE = 1.212
z = [ (x1 - x2) - d ] / SE

z = - 2.24

where s1 is the standard deviation of sample 1, s2 is the standard deviation of sample 2, n1 is thesize of sample 1, n2 is the size of sample 2, x1 is the mean of sample 1, x2 is the mean of sample 2, d is the hypothesized difference between population means, and SE is the standard error.

The observed difference in sample means produced a t statistic of -2.24. We use the z Distribution Calculator to find P(z < - 2.24)

Therefore, the P-value in this analysis is 0.0125.

Interpret results. Since the P-value (0.0125) is more than the significance level (0.01), we cannot reject the null hypothesis.

Fail to reject the null hypotehsis, There is not sufficient evidence to support the claim that mean skull breadth was less in 4000 B.C than A.D 150.

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