Question 8 of 20 [Use data from problem 1] The coefficient of variation of Y is

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Question 8 of 20

[Use data from problem 1] The coefficient of variation of Y is _____ times the the coefficient of variation of X.

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Question 10 of 20

[Use data from problem 1] Conduct a t test to test the hypothesis that mean value of Z1 equals mean value of Z2 in the population. The p value for this test is:

Question 8 of 20

1.0 Points Person ID Group 21 157.90 156.64 160.45 153.13 170.14 150.09 163.74 134.47 174.17 150.05 141.47 156.59 161.88 150.99 174.95 166.90 128.43 169.11 153.73 151.45 172.85 146.05 171.48 153.55 166.52 157.469 12.159 10 163.90 Manager 148.64 Manager 155.45 Manager 160.13 Manager 168.14 Manager 149.09 Supervisor 161.74 Supervisor 142.47 Supervisoir 177.17 Supervisor 151.05 Supervisor 148.47 Employee 148.59 Employee 162.88 Employee 158.99 Employee 174.95 Employee 165.90 Employee 124.43 Employee 168.11 Employee 150.73 Employee 146.45 Employee 164.85 Employee 137.05 Employee 178.48 Employee 151.55 Employee 164.52 Employee 156.949 12.776 2 2 4 10 10 12 13 4 16 17 10 19 4 21 23 4 Arithmetic mean Standard deviation 2.784 2.880 5.200 5.280

Explanation / Answer

1. .D.1.018808777429467 i.e 1.019

coefficient of variation is defined as (standard deviation /mean)

so, coefficient of variation of y is defined as (standard deviation of y /mean of y)

=2.88/5.28

coefficient of variation of x is defined as (standard deviation of x/mean of x)

=2.784/5.2

coefficient of variation of y/coefficient of variation of x =(2.88*5.2)/(5.28*2.784)=1.018808777428467=1.019

2.the p vallue in defined as(mean of x-mean of y)*(square root of 25)/(standard deviation of x +standard deviation of y)

=(5.2-5.28)*5/(2.784+2.88)=.63

C

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