MOF 1106 Fall 2017 Rets7219 MatLuz Bozs&11221/179 39M ework Homework: Section 12

Question

MOF 1106 Fall 2017 Rets7219 MatLuz Bozs&11221/179 39M ework Homework: Section 12.4 Normal Distribution Due Last Work Score: 0 of 1 pt cunent s 12.4.25 Anempts 12 of 19 (10 contplete) Hw Score: 52 63%, 100f 19 pts ditrbated w. . mean of 553 and a standarddednon of 110 Use the997R1 bmne percentage of people taking the test whe score between 333 The percentage of people taking-who scor. bebeen 333 and S63 h[A Quests Quest Enter your answer in the answer box and then cick Cneck Answer All parts showing 0 6

Explanation / Answer

P(333 < x < 553)

= P((333 - mean)/SD < (x - mean)/SD < (553 - mean)/SD)

= P((333 - 553)/110 < Z < (553 - 553)/110)

= P(-2 < Z < 0)

= P(Z < 0) - P(Z < -2)

= 0.5 - 0.0228

= 0.4772 = 47.72%

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