action= Consider the game of rock-paper-scissors to be arandom experiment. How m

Question

action= Consider the game of rock-paper-scissors to be arandom experiment. How many outoomes are in the sample space of this random experiment? 0 9 O 10 Assume that both roommates' choices of rock, paper, or scissors are rendom, independent, and equly lilaly et A sa, and Se denate roommate A choosing paper, roommate A choosing scissors, and roommate S choosing scissors, respedtively. Additionally, let the simple evan rock, roommate b 8 choosing rock, roommate A choosing paper,roommate S choosing consisting of roommates A and & both selecting rock be denoted parenthetically as (R, Re), and so on for the other possblites Define event A as the event that roommate A wins the game and gets to sit in the front seat Event A is composed of the following simple events: What is the probability of event A? 0.57 O 0.11 O 0.33 0 0.30 Let event Cbe the event that the game ends in a tie Event C is composed of the folowing simple events: what is the probablity of event c? O 0.11 O 0.33 O 0.67 were assigned using the 741 PM 10/10/2017

Explanation / Answer

1 )total number of outcomes =3*3 =9

hence option 9 is correct

2) A ={(Ra, Sb) ,(Pa, , Rb) ,(Sa, Pb)}

3) probability of event A =3/9 =0.33 (as there are 3 events in A out of 9)

4)C ={(Ra,Rb) ,(Pa,Pb),(Sa,Sb)}

5)probability of event C =3/9 =0.33 (as there are 3 events in C out of 9)

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