In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects w

Question

In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes in their levels of LDL cholesterol (in mg/dL) have a mean of 5.2 and a standard deviation of 16.8.

Complete parts (a) and (b) below.

b. Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol?

What is the confidence interval estimate of the population mean ? ___mg/dL<<___mg/dL

(Round to two decimal places as needed.)

Explanation / Answer

given mean = 5.2 and sd = 16.8 and n = 50

we knwo that CI is given as

mean +- z*SD/sqrt(n)

5.2 +- 1.96*16.8/sqrt(50), the value of 1.96 comes from the z table for 95% confidence interval

solving for plus and minus signs ,

0.543 <mu < 9.856

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