Question
Need Help? Submt Anawer Save Progress Practice Another Version ormulation and Quindlorac on Spray Droplet size and Deposition investigated the elfects of y drift is a constant concern for pesticide applicators and agricultural producers. The inverse relationship between droplet size and dritt potential is well known. The paoer "Effects of 2,4.D F erbicide formulation on spray atomization. A fiqure in a paper supgested the normal distribution with mean 1030 um and standard deviation 150 um was a sprayed through a 750 ml/min nozzle. e model for droplet size for water (the "control treatment") eviation 150 um was a reasonabl a) what is the probability that the size of a single droplet is less than 15001n ? At least gon um? Round your answers to four decimal places. less than 1500 m at least 900 (b) What is the probability that the size of a single droplet is between 900 and 1500 m7(Round your answer to four decimal places.) (c) How would you characterize the smallest 2% of all droplets? (Round your answer to two decimal places.) m in size. The smallest 2% of droplets are those smaller than what is the probability that st least one exoeeda 1500 pm2 (Round your answer to four decimal (d) If the sizes of five independenty selected droplets You may need to use the appropriate table in the Appendix of Tables to answer this question 0 cm, Tha second machine produces corks with Sameters that have a normal distribution There are two machines available for cutting corks intended for use in wine bottles. The first produces corks with dameters that are normally distributed with mean 3 cm and ptable corks have diameters between 2.9 and 3.1 cm. 0 02 cm. Ag
Explanation / Answer
mean = 1050 ,sd = 150
Z = (X - 1050)/150
a) P(X < 1500)
= P(Z < 3)
= 0.9987
P(X > 900) =
P (Z>1)=0.8413
b) P(900 <X< 1500)
= P(X < 1500) - P(X < 900)
= P ( 1<Z<3 )=0.84
c)
P(Z <z*) = 0.02
z* = - 2.054
X = 1050 -2.054 *150
= 741.9
d) required probability = 1 - 0.9987^5
= 0.0064831
