Here is a contingency table of the age data from the spring 2012 online Statisti
ID: 3334382 • Letter: H
Question
Here is a contingency table of the age data from the spring 2012 online Statistics class. (I’m using that class’s data rather than ours because it is a slightly larger data set.)
Data table
16-25
First age category (F)
26-35
Second age category (S)
36 -45
Third age category (T)
TOTAL
MAN (M)
4
2
2
8
WOMAN (W)
11
9
2
22
TOTAL
15
11
4
30
Find: P(T) = Probability the person is in the third category
Data table
16-25
First age category (F)
26-35
Second age category (S)
36 -45
Third age category (T)
TOTAL
MAN (M)
4
2
2
8
WOMAN (W)
11
9
2
22
TOTAL
15
11
4
30
Explanation / Answer
P(T) = Probability that the person is in third category
= Number of people in the third category / Total number of people
= 4/30
= 0.1333
Therefore 0.1333 is the required probability here.
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