The data below examine the relationship between two variables, the quality of ma
ID: 3336138 • Letter: T
Question
The data below examine the relationship between two variables, the quality of marriage and the quality of parent–child relationships. You can use SPSS or excel for this assignment or you can work them out old fashion, by hand (show your work).
Quality of Marriage Quality of the Parent–Child Relationship
76 43
81 33
78 23
76 34
76 31
78 51
76 56
78 43
98 44
88 45
76 32
66 33
44 28
67 39
65 31
59 38
87 21
77 27
79 43
85 46
68 41
76 41
77 48
98 56
98 56
99 55
98 45
87 68
67 54
78 33
Use the data to:
-Write a null and research hypotheses for the variables.
-Choose the t test you think is appropriate out of the t tests we have covered in this course to determine the t-value for the data (you can copy the results from your SPSS output and past them here. Here are the tests:
One sample (Mean) test
Two samples (independent t-test) test
Paired/related sample t tests
-From the t test you ran above, tell me the confidence intervals for the data and interpret what they mean.
Explanation / Answer
Here we have to test the hypothesis that,
H0 : mu1 = mu2 Vs H1 : mu1 not= mu2
where mu1 and mu2 are populatione means.
Assume alpha = level of significance = 0.05
Here we can use two sample t-test assuming equal variances.
Test statistic follows t-distribution with n1+n2-2 degrees of freedoms.
We can do two sample t test in MINITAB.
steps :
ENTER data into MINITAB sheet --> STat --> Basic statistics --> 2-Sample t --> Samples in different columns --> First : select quality of marriage data --> Second :select Quality of the Parent–Child Relationship --> Click on assume equal variances --> Options -->Confidence level : 95.0 --> Test difference : 0.0 --> ALternative : not equal --> ok --> ok
Two-Sample T-Test and CI: quality of marriage, quality of the parent child
Two-sample T for quality of marriage vs quality of the parent child
N Mean StDev SE Mean
quality 30 78.5 12.5 2.3
quality 30 41.3 11.2 2.0
Difference = mu quality of marriage - mu quality of the parent child
Estimate for difference: 37.27
95% CI for difference: (31.13, 43.40)
T-Test of difference = 0 (vs not =): T-Value = 12.16 P-Value = 0.000 DF = 58
Both use Pooled StDev = 11.9
Test statistic = 12.16
P-value = 0.000
P-value < alpha
Reject H0 at 5% level of significance.
Conclusion : There is sufficient eveidence to say that two population means differ.
95% confidence interval for mu1-mu2 is (31.13, 43.40)
We are 95% confident that the population mean difference is lies between 31.13 and 43.40
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