KS4 points) Name has a normal distribution; software company has a program that
ID: 3336901 • Letter: K
Question
KS4 points) Name has a normal distribution; software company has a program that generates numbers X that they claim ; assume that X Normal(, ). Using the software, you generate a sample of 10 numbers that has a sample mean of standard deviation of s 0.841 -0.712 and a sample a. Based on the sample, determine a 94% Confidence Interval for 712 3 2. b. The company claims that this software program in fact generates numbers with a population mean = 0, company's claim is valid. Based on your answer from a), explain if the software 2. (I point) Let F and s be the sample mean and sample standard deviation computed from the results ofa random sample from a normal population with mean . Mark with an "X" all the statements that are TRUE about a 90% Confidence Interval for . A larger sample size n is likely to reduce the Confidence Interval width. About 90% of the sample points would be contained within the Confidence Interval. There is a 90% chance that the population mean is in the Confidence Interval. X If a 99% Confidence Interval were constructed from the same sample results, the interval would be wider than the 90% Confidence Interval. If you were to take 50 random samples and construct 90% Confidence Intervals, about 45 of them would contain the population meanExplanation / Answer
B.
interpretations:
1. we are 94% sure that the interval [0.2982 , 1.1258 ] contains the true population mean
2. if a large number of samples are collected, and a confidence interval is created
for each sample, 94 % of these intervals will contains the true population mean
as U=0 lies outside the above interval bound , we don't have evidence to support the claim
Q2.
A larer sample size n is likely to reduce the CI
[REASON]true, since value of n is inversely proportional to CI, when it increases CI reduces
and when it decreases CI increases
If a 99% CI is constructed the interval would be wider than 90% CI
[REASON] true, since value of margin of error is more for 99% CI rather 90%CI
Option B, D are also true. the reason behind CI levels will cover up most part of data except the outlier data
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