PrtSc 3. Anand m sample of n= 100 observations is selected from a population wit
ID: 3338467 • Letter: P
Question
PrtSc 3. Anand m sample of n= 100 observations is selected from a population with-30 and =22. Complete parts ath 1 Click the icon to view the table of normal curve areas. a·Find , and 8a-30 (Round to one decimal place as needed.) b. Describe the shape of the sampling distribution of x. Inform A. Uniform distribution 0 B. Skewed left nvSD C. Approximately normal O D. Skewed right c. Find P(x 2 28). P(x228) d. Find P(22.1 sx 26.8). P(22.1 x 26.8) e. Find P(xs28.2) PK s28.2)(Round to four decimal places as needed.) O 1,2 | (Round to four decimal places as needed.) 15 ] (Round to four decimal places as needed.) f. Find P(x227.0). P 270)- Do1 (Round to four decimal plaoes as needed) P(x 27.0) = 1: Normal Curve Areas 1bo B 100.00 106-3R IExplanation / Answer
(c) P(X > 28)
Since = 30 and = 2.2 we have:
P ( X > 28 ) = P ( X > 2830 ) = P ( X/ > 2830/2.2)
Since Z = x/ and 2830/2.2 = 0.91 we have:
P ( X > 28 ) = P ( Z > 0.91 )
Use the standard normal table to conclude that:
P (Z > 0.91) = 0.8186
(d) Same steps as above -
P ( 22.1 < X < 26.8 ) = P ( 3.59 < Z < 1.45 )
Use the standard normal table to conclude that:
P ( 3.59 < Z < 1.45 ) = 0.0733
(e)
P (X < 28.2) = P (Z < 0.82)
Use the standard normal table to conclude that:
P (Z < 0.82) = 0.2061
(f)
P ( X > 27.0 ) = P ( Z > 1.36 )
Use the standard normal table to conclude that:
P (Z > 1.36) = 0.9131
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