Chapter 9 Post-Test Question: 1 pt 2of19(0 complete) This Test: 19 pts Use the s

Question

Chapter 9 Post-Test Question: 1 pt 2of19(0 complete) This Test: 19 pts Use the sample data and confidence level given below to complete parts (a) through (d) in a study of cel phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2436 subjects randomly selected from an online group involved with ears 992 surveys were reumed Consiruct 99% confidence iterval for the pr tion of reamed surveys. click the oon to view a table of z sores a) Find the best point estimate of the population proportion p Round to three decimal places as needed.) b) Identity the value of the margin of eror E Round to four decimal places as needed.) c) Construct the coefidence interval Round to three decimal places as needed ) d) Write Click to select your answerls). a statement that correcty interprets the confidence interval. Choose the cormect answer below 2 3 4

Explanation / Answer

Answer to the question)

Sample size n = 2436

Returned survey , x = 992

Confidence level = 99% , thus z critical = 2.575

.

Part a)

proportion = x/n = 992 /2436 = 0.407

.

Part b)

Margin of error = z * sqrt(p*(1-p)/n)

Margin of error = 2.575 * sqrt((992/2436)*(1-(992/2436)/2436)

MArgin of error = 1.643

.

Part c)

Confidence interval :

Lower interval : p - Margin of error

Lower interval = 0.407 - 1.643 = -1.236

Upper interval : p + margin of error

Upper interval = 0.407 + 1.643 = 2.050

.

Part d)

The correct interpretation is statement A

there are 99% chances that the true population proportion will lie in the given confidence interval

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