Question
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3.
Find a formula for the nth term of the sequence. 2, 9, 28, 65, 126, ... Choose the correct answer below. an = 2n2 + 6, n 1 an = 3n + 6, n 1 an = 2n - 9, n 1 an = n2 + 9, n 1 an = n3 + 1, n 1 an = n2 - 1, n 1 an = n3 -6, n 1 an = 3n - 1, n 1 Find a formula for the nth term of the sequence. 2, 9, 28, 65, 126, ... Choose the correct answer below. an = 2n2 + 6, n 1 an = 3n + 6, n 1 an = 2n - 9, n 1 an = n2 + 9, n 1 an = n3 + 1, n 1 an = n2 - 1, n 1 an = n3 -6, n 1 an = 3n - 1, n 1 The first term of a sequence along with a recursion formula for the remaining terms is given below. Write out the first ten terms of the sequence. a1 = 8, an+1 = an + (1/2n) a1 =
Explanation / Answer
1]an=(n^3)+1 n>=1
2]an=(n^3)+1 n>=1
3]8,8.5,8.75, 8.875 , 8.9375 , 8.96875 , 8.984375 , 8.9921875 , 8.99609375 , 9.231575
