Problem # 1 Consider a two-station segment of an electronics assembly line. The

Question

Problem # 1 Consider a two-station segment of an electronics assembly line. The first station (Inspect) consists of an automated machine that takes an average of 5.1 minutes to process a job. This machine is subject to failures, so 20 percent of the jobs drop out after the first station. The second station is a manual operation staffed by a single operator who takes on average 5.7 minutes to inspect each job. There are no failures at the second station. Jobs arrive to this segment of the first station at a rate of 10 jobs per hour. 1) Compute the capacity of each station. 2) Compute the utilization of each station and determine the bottleneck of this assembly line. Chint ra of the first station Ta of the first station) 3) If a job stays at the second station for 7.2 minutes on average, what is the work-in-process level at the second station on average? Page 1 of 2

Explanation / Answer

part 1

Capacity for Section 1

Process rate for section 1=5.1 min for a job

failure rate=20%

Capacity for Section1=(60/5.1)jobs /hour=11.76 Jobs/hr

As failure rate is 20%, no of jobs move out from section 1=80%

so final capacity=.8*11.76=9.411 or 9 job/hr

For section 2

capacity =60/5.7= 10.5 job/hr

Part 2

utilization=actual output/potential output%

input for section1=10 job/hr

Utilization Section 1=9.411/9.41=100%

at section 2 arrival rate=9.411jobs/hr

Section 2 utilization=9.411/10=94.11%

Part 3

at section 2

processing rate=7.2min or 60/7.2 or 8.33 jobs/hr

input rate=9.411

In an hour, WIP=9.411-8.33=1.077 jobs/hr

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.