Give as much information as you can about the P -value of a t test in each of th

Question

Give as much information as you can about the P-value of a t test in each of the following situations. (Round your answers to three decimal places.)

(a) Upper-tailed test,

df = 9, t = 2.0

P-value < 0.005

0.005 < P-value < 0.01  

0.01 < P-value < 0.025

0.025 < P-value < 0.05

P-value > 0.05

(b) Upper-tailed test,

n = 13, t = 3.2

P-value < 0.005

0.005 < P-value < 0.01  

0.01 < P-value < 0.025

0.025 < P-value < 0.05

P-value > 0.05

(c) Lower-tailed test,

df = 10,t = 2.3

P-value < 0.005

0.005 < P-value < 0.01

0.01 < P-value < 0.025

0.025 < P-value < 0.05

P-value > 0.05

(d) Lower-tailed test,

n = 24,t = 4.3

P-value < 0.005

0.005 < P-value < 0.01

0.01 < P-value < 0.025

0.025 < P-value < 0.05

P-value > 0.05

(e) Two-tailed test,

df = 14,t = 1.6

P-value < 0.01

0.01 < P-value < 0.02

0.02 < P-value < 0.05

0.05 < P-value < 0.1

P-value > 0.1

(f) Two-tailed test,

n = 15,t = 1.6

P-value < 0.01

0.01 < P-value < 0.02

0.02 < P-value < 0.05

0.05 < P-value < 0.1

P-value > 0.1

(g) Two-tailed test,

n = 14,t = 6.2

P-value < 0.01

0.01 < P-value < 0.02

0.02 < P-value < 0.05

0.05 < P-value < 0.1

P-value > 0.1

Explanation / Answer

a) Here, P-value for , degrees of freedom(df) = 9 and test statistic t = 2.0 and if test is lower tailed ( left tailed) is,

P-value = 0.038

Thus, implies that,

0.025 < P-value < 0.05

(b) Upper-tailed test,

n = 13, t = 3.2

df = n - 1 =13 -1 = 12

Therefore, P-value = 0.004

Thus,

P-value < 0.005

(c) Lower-tailed test,

df = 10,t = 2.3

Therefore, P-value = 0.022

Thus,

0.01 < P-value < 0.025

(d) Lower-tailed test,

n = 24,t = 4.3

df = 24 -1 =23

Therefore, P-value = 0.000

Thus,

P-value < 0.005

(e) Two-tailed test,

df = 14,t = 1.6

Therefore, P-value = 0.132

Thus,

P-value > 0.1

(f) Two-tailed test,

n = 15,t = 1.6

df = 15 -1 = 14

Therefore, P-value = 0.132

Thus,

P-value > 0.1

(g) Two-tailed test,

n = 14,t = 6.2

df = 14 - 1 = 13

Therefore, P-value = 0.000

Thus,

P-value < 0.01

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