1. The mean salary at a local industrial plant is $30,400 with a standard deviat

Question

1. The mean salary at a local industrial plant is $30,400 with a standard deviation of $4300. The median salary is $25,400 and the 59" percentile is $31,100 Step 1 . Approximately 59% of the salaries are below $31,100 th Step 2. Joe's salary of $35,630 is 1.10 standard deviations above the mean. Step 3. The percentile rank of $25,400 is 50 Step 4. Approximately 9% of the salaries are between $30,400 and $31,100 Step 5. If Tom's salary has a z-score of 0.5, how much does he earn (in dollars)? A) True A) True A) True A) True B) False B) False B) False B) False 2. The number of hours per week that the television is turned on is determined for each family in a sample. The mean of the data is 33 hours and the median is 29.2 hours. Twenty-four of the families in the sample turned on the television for 18 hours or less for the week. The 6 th percentile of the data is 18 hours. 56t percentile is less than 28 hours. A) True Step 1. The B) False Step 2. Approximately how many families are in the sample? Round your answer to the nearest integer Step 3. A total of 200 families turned on their televisions for at most 33 hours. B) False th A) True Step 4. What is the value of the 50 percentile? Step 5. The first quartile is less than 18 hours. A) True B) False

Explanation / Answer

Answers are below. Please write back to me in case you have doubts:

1. True. This is the defnition of percentile

2. Lets see what is value 1.1 deviation above mean

= 1.1*Stdv + Mean

= 1.1*43000 + 30400

= 77,700

So, answer is False

3. Percentile 50 is median. Since median is 25400 therefore, answer is True

4. 30400 is mean, 31100 is Z = (31100-30400)/43000 deviation below mean

So, P(Z<0) - P(Z<-.0163) = .5-.4953 = .0047 or .47% and not 9%

Hence, answer is False

5. If his Z-score is .5 then he earns

= .5*Stdv + Mean

= .5*$43000 + $30,400

= $51,900

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.