Consider a family with three children in which both parents are carriers for cys

Question

Consider a family with three children in which both parents are carriers for cystic fibrosis. What is the probability that they will have no affected children?

1) 0

2) 1/64

3) 9/64

4) 16/64 = 1/4

5) 27/64

Consider a family with three children in which both parents are carriers for cystic fibrosis. What is the probability that they will have exactly one affected child?

1) 1

2) 1/64

3) 9/64

4) 16/64 = 1/4

5) 27/64

Consider a family with three children in which both parents are carriers for cystic fibrosis. What is the probability that they will have exactly two affected children?

1) 1

2) 1/64

3) 9/64

4) 16/64 = 1/4

5) 27/64

Consider a family with three children in which both parents are carriers for cystic fibrosis. What is the probability that all three children will be affected

1) 1

2) 1/64

3) 9/64

4) 16/64 = 1/4

5) 27/64

Explanation / Answer

P( affecting for 1 child) = 3/4 =q

P( No affect on 1 child) =p=1/4

P( 0) = 3C3 * (1/4)^3 = 1/64

P(1) = 3C1 * (1/4)^2 * (3/4)^1 = 9/64

P(2) = 3C2 * 1/4^1 * (3/4)^2 = 27/64

P(3) = 3C3 * (3/4)^3 = 27/64

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.