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5.07264 72949 3.64107 6 50421 Biostats Fall16 Week 3 Assignment The tables below

ID: 3355124 • Letter: 5

Question

5.07264 72949 3.64107 6 50421 Biostats Fall16 Week 3 Assignment The tables below represent SPSS output from an Independent Groups t-test. The data set include from women about their employment, and mental health. The variables included in the analysis are: d data D score Center for Epidemiologic Studies Depression Scale (continuous level of measure) worknow whether the women were currently employed (nominal level of measure) Research Hypothesis: The employment status of women is related to their level of depression. Using the output tables below answer the following questions 1. How many women were employed versus not employed in this sample?ineioya 534 2. What are the mean CES-D scores for employed and non-employed women? F 15.823 3. What is the value of the F statistic for Levene's test and what is the related significance result? What does this mean? 4. Based on the result of the Levene's test for Equality, which set of results from the t-test should be reported (Equal variances assumed or Equal variances not assumed)? What are the results (include the t statistic and p value)? Is the result statistically significant? 5, what is the 95% confidence interval around the mean difference for the appropriate output? what does the confidence interval represent? Employud· 4%

Explanation / Answer

3) Levene's test statisticvalue is 23.615 and its pvalue is .000 which is significant .

4) Since we do Levene's test to check equality of variance. In this test our null hypothesis would be

Null Hypothesis H0: Variances are equal

Alternative HypothesisHa: variances are not equal

Since p value is significant so we REJECT NULL HYPOTHESIS and report that variances are not equal.

Result of t test. t stat = 6.954 (variances are not equal)

p value= .000 which is significant at 0.05 level of significance. We therefore Reject Null hypothesis.

4) Since Levene's test was significant . We reported variances are not equal. We will see the row of assume variances are not equal . The 95% confidence interval is (3.64107,6.50421) .You can be 95% confident that the population mean () falls between (3.64107 and 6.50421)

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