6. 1.5:2 points 214 Submissions used My Notes Ask Your Teacher ÷ In an experimen
ID: 3356534 • Letter: 6
Question
6. 1.5:2 points 214 Submissions used My Notes Ask Your Teacher ÷ In an experiment to compare the tensile strengths of 1-6 different types of copper wire, J = 5 samples of each type were used. The between-samples and within-samples estimates of 2 were computed as MSTr 2640.3 and MSE-1119.2, respectively. a If 0.05 then according to the F distnbution with 1-1 and 1 1-1 degrees of freedom what value of Fr null. This value represents what is called the rejection region. rejection region f22.36 st our est statistic larger han nor er reject e 6 versus Ha: at least two 's are unequal. Use a significance level 0,05(Round your answers to two decimal Calculate the test statistic F to test H0: -2·· places.) test statistic f-2.36 State the conclusion in the problem context Reject H0. The data indicates there is not a difference in the mean tensile strengths Fail to reject H0. The data indicates a difference in the mean tensile strengths. Fail to reject Ho. The data indicates there is not a difference in the mean tensile strengths Reject Ho. The data indicates a difference in the mean tensile strengths. (b) What can be said about the P-value for the test? P-value > 0.100 0.050Explanation / Answer
a) Correct answer: 2.62065
The Critical value of F is 2.62065 at (5, 24) df and 5% los in F- tables
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