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The data show the time intervals after an eruption (to the next eruption) of a c

ID: 3356893 • Letter: T

Question

The data show the time intervals after an eruption (to the next eruption) of a certain geyser. Find the regression equation, letting the first variable be the independent (x) variable. Find the best predicted time of the interval after an eruption given that the current eruption has a height of 84 feet. Use a significance level of 0.05.

what is the regression equation?

y= ?? + ??x (round to two decimal places as needed)

what is the best predicted time for th interval after an eruption that is 84 feet high? (round to one decimal place as needed)

height (ft) 96 111 76 91 66 108 116 91 interval after (min) 68 80 66 72 58 79 84 79

Explanation / Answer

The statistical software output for this problem is:

Simple linear regression results:
Dependent Variable: interval after (min)
Independent Variable: height (ft)
interval after (min) = 29.827266 + 0.46010844 height (ft)
Sample size: 8
R (correlation coefficient) = 0.90562995
R-sq = 0.8201656
Estimate of error standard deviation: 4.0286541

Parameter estimates:


Analysis of variance table for regression model:


Predicted values:

Hence,

Regression equation:

y = 29.83 + 0.46 x

Best predicted time for 84 feet high = 68.5

Parameter Estimate Std. Err. Alternative DF T-Stat P-value Intercept 29.827266 8.4222515 0 6 3.5414836 0.0122 Slope 0.46010844 0.087956954 0 6 5.2310639 0.002
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