The data set below contains the amount that a sample of nine customers spent on

Question

The data set below contains the amount that a sample of nine customers spent on lunch ($) at a fast-food restaurant. Complete parts (a) through (d) below.

4.12
5.07
5.86
6.48
7.48
7.54
8.55
8.44
9.88

a. Compute the mean and median

b. Compute the variance, standard deviation, range, and coefficient of variation

c. Are the data skewed? If so, how?

d. Based on the results of (a) through (c), what conclusions can be reached concerning the amount that customers spent for lunch?

The average cost is ?$   

The average cost is$

The average scatter of cost around the mean is$

The difference between the highest cost and lowest cost is$

Explanation / Answer

For the given data we have:

Mean = Sum of all numbers/Total numbers = 63.42/9 = 7.046

Median = 7.48

Variance = 3.357

Standard deviation = 1.832

COV = (1.832/7.046)*100 = 26%

The data is is skewed left since the mean is smaller than the median.

So,

Average cost is $7.046

Average scatter around mean is $1.832

Difference between highest and lowest cost is: 9.88-4.12 = $5.76

Hope this helps !

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