I have 50 songs 10 of those are X 40 of those are Y Let there be 20 songs per ho

Question

I have 50 songs 10 of those are X 40 of those are Y
Let there be 20 songs per hour as the average song length is 180 seconds
What is the probability that a “X” song is played within that hour
What is the probability that a “Y” song is played within that hour I have 50 songs 10 of those are X 40 of those are Y
Let there be 20 songs per hour as the average song length is 180 seconds
What is the probability that a “X” song is played within that hour
What is the probability that a “Y” song is played within that hour I have 50 songs 10 of those are X 40 of those are Y
Let there be 20 songs per hour as the average song length is 180 seconds
What is the probability that a “X” song is played within that hour
What is the probability that a “Y” song is played within that hour

Explanation / Answer

In order to play an X song, out of 20 songs there should be 1 X song

1 X song can be selected in 10C1 ways and remaining 19 Y songs can be selected in 40C19 ways.

Hence probabiltiy that a "X" song is played, P = 10C1*40C19 / 50C20 = 0.0279

As there are only 10 X songs, hence there has to be Y song in 20 songs played in an hour. Hence probability that a Y sogn is played within that hour is 1.

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